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2x^2-46x+4=890
We move all terms to the left:
2x^2-46x+4-(890)=0
We add all the numbers together, and all the variables
2x^2-46x-886=0
a = 2; b = -46; c = -886;
Δ = b2-4ac
Δ = -462-4·2·(-886)
Δ = 9204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9204}=\sqrt{4*2301}=\sqrt{4}*\sqrt{2301}=2\sqrt{2301}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-2\sqrt{2301}}{2*2}=\frac{46-2\sqrt{2301}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+2\sqrt{2301}}{2*2}=\frac{46+2\sqrt{2301}}{4} $
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